Question

Accelerating uniformly along a straight road at the rate of 2.5 ms⁻², a bus starts from rest and reaches a velocity of 15 ms⁻¹ in 6 seconds. Determine the distance travelled by the bus.

Answer 1

Answer

• Distance travelled will be 45 m

Explanation

Given

• Acceleration = 2.5 m/s²
• Initial Velocity = 0 m/s
• Final Velocity = 15 m/s
• Time = 6 sec

To Find

• Distance travelled by the bus?

Formula Used

• v²-u² = 2as [Third Equation of motion]

Where,

»» u is the initial velocity

»» v is the final velocity

»» a is the acceleration

»» s is the distance travelled

Solution

➝ v²-u² = 2as

➝ 15²-0² = 2 × 2.5 × s

➝ 225-0 = 5s

➝ 225 = 5s

➝ 225/5 = s

➝ Distance = 45 m

Another Method

Here we shall use the second Equation of motion

➝ s = ut+½at²

➝ s = 0×6 + ½ × 2.5 × 6²

➝ s = ½ × 2.5 × 36

➝ s = 2.5 × 18

➝ Distance = 45 m