Question

Acceleration (a), velocity (V) and displacement (x)are related according to equation a==+doarding to continn a-VXDimension of time in dimensional formula of AB is(where A and B are constants)​

Answer 1

Answer:

3

Explanation:

The question is not properly asked here. the question is this:

Acceleration (a),velocity (V),and displacement (x) are related according to equation a=V/A+x/B . dimension of time in dimensional formula of AB is(where A and B are constants)?

Solution:

∵ a = V/A + x/B

∴ V/a and x/B will have same dimensions as that of acceleration

Dimensions of acceleration = [LT^-2]

Dimensions of V = [LT^-1]

Dimensions of x =[L]

∴ Dimensions of A = Dimensions of V/ Dimensions of a

                               = [LT^-1]/[LT^-2] = [T^1]

Similarly, Dimensions of B = Dimensions of x / Dimensions of a

                                           = [L]/[LT^-2] = [T^2]

Therefore, Dimensions of AB = [T] × [T²]

                                                 = [T^3]

Therefore, dimension of time in dimensional formula of AB is 3

Answer 2

Answer:

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