Question

acceleration due to gravity
​

Answer 1

Answer:

Acceleration due to gravity is a vector, which means it has both a magnitude and a direction. The acceleration due to gravity at the surface of Earth is represented by the letter g. It has a standard value defined as 9.80665 m/s2 (32.1740 ft/s2).

Answer 2

ᴀᴄᴄᴇʟᴇʀᴀᴛɪᴏɴ ᴅᴜᴇ ᴛᴏ ɢʀᴀᴠɪᴛʏ

Acceleration due to gravity when an object is dropped from some height, a uniform acceleration is produced in it by the gravitational pull of the earth and this acceleration does not depend on the mass of the falling object) Thus, we can definel acceleration due to gravity as,

"Tʜᴇ ᴀᴄᴄᴇʟᴇʀᴀᴛɪᴏɴ ᴡɪᴛʜ ᴡʜɪᴄʜ ᴀ ʙᴏᴅʏ ꜰᴀʟʟs ᴛᴏʀᴡᴀʀᴅs ᴛʜᴇ ᴇᴀʀᴛʜ ᴅᴜᴇ ᴛᴏ ᴇᴀʀᴛʜ 's ɢʀᴀᴠɪᴛᴀᴛɪᴏɴᴀʟ ꜰᴏʀᴄᴇ ɪs ᴋɴᴏᴡɴ ᴀs ᴀᴄᴄᴇʟᴇʀᴀᴛɪᴏɴ ᴅᴜᴇ ᴛᴏ ɢʀᴀᴠɪᴛʏ."

It is denoted by' g '. The value of 'g does not depend on the mass of the body. However, it changes from place to place. Generally, the value of acceleration due to gravity is taken as 9.8 m s¯² on or near the surface of earth. Thus, we can conclude that when an object falls to the ground under the gravitational force, its velocity increases at constant rate of 9. 8 m s¯² . In other words, we can say that whena body is dropped freely, it falls withanacceleration of 9.8 m s¯².

Now, another question arises what would happen to the acceleration when a body is thrown vertically upward? When a body is thrown vertically upward, the body undergoes a retardation of 9.8 m s¯². Thus, the velocity of a body thrown vertically upwards will decrease until it reaches zero in this case, the acceleration is called retardation due to decrease in the velocity.