Question

If (3x-1)^3+(4x+3)^3+ (2x + 1)^3 =
3 (3x-1) (4x-3) (2x + 1), then x =?​

Answer 1

The answer is attached....

Plz.. Mark me as branliest

Answer 2

Answer:

The value of  $x = - \frac{1}{3}$

Step-by-step explanation:

Standard form of given equation is

$a^{3} + b^{3} + c^{3} - 3 abc$ = 0 ------- (1)

Compare the given equation with the above equation, we get

a = 3 x - 1, b = 4 x + 3, c = 2 x + 1

Now the given equation in the question satisfies the condition of equation 1.

⇒ $a + b + c = 0$

⇒ 3 x - 1 + 4 x + 3 + 2 x + 1 = 0

⇒ 9 x = - 3

⇒ $x = - \frac{1}{3}$

This is the value of x.