Physics, asked by anchal3361, 1 year ago

Acceleration due to gravity 3200 m above the surface of the earth

Answers

Answered by mushahid36
0
g=GM/R^2
g'=GM/(R+h)^2
g'/g=GM/(R+h)^2×R^2/GM
g'/g=R^2/(R+h)^2
g'/g=(6.4×10^6)^2/(9.6×10^6)^2
g'/g=4/9
g'=g×4/9
g=4.4m/s^2
Similar questions