acceleration of a body sliding over a rough inclined plane
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F = mgsinQ
a = gsinQ - ugcosQ
Q = angle of inclined plane
a = gsinQ - ugcosQ
Q = angle of inclined plane
Light1729:
As the plane is rough the acceleration will be less that gsinQ
thq
see my answer
Answered by
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Net force downwards = mgsinQ-umgcosQ, where u is the friction coefficient.
so acceleration is gsinQ-ugcosQ
so acceleration is gsinQ-ugcosQ
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