Question

Acceleration of a particle moving in a straight line is varying with time as a=6t²+4t+2 . Initial velocity of particle is 5ms the velocity at time =1 s

Answer 1

Answer:

11 m/s.

Explanation:

a = 6t²+4t+2 = d²x/dt²

v = dx/dt = 2t³ + 2t² + 2t + c , c =5

v = 2t³ + 2t² + 2t + 5

v = 2 + 2 + 2+ 5 = 11 m/s.