Acceleration of Particle increases linearly with time t as 6t if the initial of the particle is zero and the particle start from the origin then the distance travelled by the particle in time will be
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I can't solve hope it helps
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Answer:
t^3
Explanation:
- a is given as function of t so a=6t
a = dv/dt so ∫dv =∫6tdt
put limit 0 to v for dv integeral and 0 to t for 6tdt
v = 6t²/2= 3t²
v = dx/dt so
∫dx=∫3t²dt
put limit 0 to x for dx and 0 to t for 3t²dt
x-0 = 3t×t -0
x = 3t³+c
hence the distance travlelled by particle in t time will be t³
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