Question

Accept a number and print its reverse​

Answer 1

Answer:

C :

#include<stdio.h>  

int main()    

{    

int n, reverse=0, rem;    

printf("Enter a number: ");    

 scanf("%d", &n);    

 while(n!=0)    

 {    

    rem=n%10;    

    reverse=reverse*10+rem;    

    n/=10;    

 }    

 printf("Reversed Number: %d",reverse);    

return 0;  

}  

Java :

import java.util.Scanner;

class ReverseNumber

{

 public static void main(String args[])

 {

   int n, reverse = 0;

   System.out.println("Enter an integer to reverse");

   Scanner in = new Scanner(System.in);

   n = in.nextInt();

   while(n != 0)

   {

     reverse = reverse * 10;

     reverse = reverse + n%10;

     n = n/10;

   }

   System.out.println("Reverse of the number is " + reverse);

 }

}

Python :

Number = int(input("Please Enter any Number: "))    

Reverse = 0    

while(Number > 0):    

   Reminder = Number %10    

   Reverse = (Reverse *10) + Reminder    

   Number = Number //10    

     

print("\n Reverse of entered number is = %d" %Reverse)

Explanation:

Answer 2

Question:-

• Write a program to accept a number and print it's reverse.

Code:-

import java.util.*;

class Reverse

{

public static void main(String s[])

{

Scanner sc = new Scanner(System.in);

System.out.print("Enter a number: ");

int n=sc.nextInt();

int s=0;

while(n!=0)

{

s=s*10+n%10;

n/=10;

}

System.out.println("Reversed number is: "+s);

}

}