Question

According to a plan, a team of woodcutters decided to harvest 216 cubic metre of wheat in several days. in the first three days, the team fulfilled the daily assignment, and then it harvested 8 cubic metre of wheat over and above the plan every day. therefore, a day before the planned date, they had already harvested 232 cubic metre of wheat. to harvest 216 cubic metre of wheat 2 days before the planned date, how many cubic metres of wheat must be harvested by team over and the above the plan every day after first three days?

Answer 1

Let the planned number of days = x


Rate of work =  216/x



First 3 days, work done = 216/x* 3 = 648/x


After 3 days;

Rate = (216/x + 8) per day


One day before the planed date = x – 1


Subtract the first 3 days = x – 1 – 3 = x – 4


Total work completed = 648/x + (x-4)( 216/x + 8) = 232




Simplified and solved (See the attaached image)

x = 9


To harvest 216 cubic metre of wheat 2 days before the planned date, how many cubic metres of wheat must be harvested by team over and the above the plan every day after first three days?




First 3 days = 648/9 = 72 m3


Work remaining = 216 – 72 = 144



2 days before the planned date = 9 – 3 – 2 = 4


4 days to complete 144


Work per day = 144/4 = 36


Normal rate of work =  216/x = 216/9 = 24



The number of cubic metres of wheat must be harvested by team over and the above the plan every day after first three days


= 36 – 24

= 12 cubic metres of wheat

Answer 2

12 is the answer......