According to Arrhenius equation rate constant k is equal to
A e- Eₐ/ /RT. Which of the following options represents the
graph of ln k vs 1/T?
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0
Answer:
ANSWER
Arhenius Equation: k=Ae^{-E_a/RT}k=Ae
−E
a
/RT
\Rightarrow ln \ k= ln \ (Ae^{-E_a/RT})⇒ln k=ln (Ae
−E
a
/RT
)
\Rightarrow ln \ k= ln \ (A) + ln \ (e)^{-E_a/RT}⇒ln k=ln (A)+ln (e)
−E
a
/RT
\Rightarrow ln \ k= ln \ (A) + \cfrac {-E_a}{RT}ln \ (e)⇒ln k=ln (A)+
RT
−E
a
ln (e)
\Rightarrow ln \ k= ln \ (A) + \cfrac {-E_a}{RT}(1)⇒ln k=ln (A)+
RT
−E
a
(1)
\Rightarrow ln \ k= \cfrac {-E_a}{R} \cfrac 1T + ln \ (A)⇒ln k=
R
−E
a
T
1
+ln (A)
It represents a straight line with negative slope.
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0
Hello Friend..!!
The answer of your question is..!!
Option. A
Thank you..!!
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