Chemistry, asked by AmshithaB, 7 months ago

According to Graham’ law at a given temperature, the ratio of the rates

of diffusion rArBrArB of gases A and B is given by:

(a) PAPB√ MAMBPAPBMAMB

(b)MAMB√PAPBMAMBPAPB

(c)PBMB√PAMAPBMBPAMA

(d)MAMB√PBPAMAMBPBPA

Answers

Answered by Anonymous
2

Answer:

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Explanation:

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Answered by simreensaini
6

Here is ur answer

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According to the Graham's law of diffusion, the rates of diffusion of two gases are directly proportional to their partial pressures and inversely proportional to their molecular weights.

The expression for the relative rates of diffusion of two gases is

r

B

r

A

=(

P

B

P

A

)(

M

A

M

B

)

2

1

.

Here, r

A

and r

B

are the rates of diffusion of two gases A and B respectively,

P

A

and P

B

are their partial pressures and M

A

and M

B

are their molecular weights respectively.

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