Question

According to law of photochemical equivalence the energy
absorbed (in ergs/mole) is given as (h = 6.62 × 10⁻²⁷ ergs, c
= 3 × 10¹⁰ cm s⁻¹, NA = 6.02 × 10²³ mol⁻¹)
[NEET Kar. 2013]
(a)1.196 × 10¹⁶/????
(b)1.196 × 10⁸/????
(c)2.859 × 10⁵/????
(d)2.859 × 10¹⁶/????

Answer 1

According to the law of photochemical equivalence the energy absorbed (in ergs/mole) is given as 1.196 × 10~8/ λ.

Option (B) is correct.

Explanation:

The photochemical equivalence law states that for every quantum of a radiation which is absorbed, there is one molecule of the substance that reacts.

Energy absorbed in the mole = h = 6.62 × 10⁻²⁷ ergs

C = 3 × 10¹⁰ cm s⁻¹

NA = 6.02 × 10²³ mol⁻¹

Thus,

E = HcNa/λ

= 6.62 × 10⁻²⁷ × 3×10¹⁰ × 6.02 × 10²³/λ

= 1.1955 × 10~8/ λ

=  1.196 × 10~8/ λ mol

Therefore, according to the law of photochemical equivalence the energy absorbed (in ergs/mole) is given as 1.196 × 10~8/ λ.

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