The reaction of C₆H₅CH = CHCH₃ with HBr produces: [2015]
(a) C₆H₅CH₂CHCH₃
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Br
(b) C₆H₅CH₂CH₂CH₂Br
(d) C₆H₅CHCH₂CH₃
|
Br
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The reaction of C₆H₅CH = CHCH₃ with HBr produces :
• The above reaction will follow Markovnikov's Rule.
• It states that the addition of a protic acid HX to an asymmetric alkene, the acid hydrogen (H) gets attached to the carbon with more hydrogen substituents, and the halide (X) group gets attached to the carbon with more alkyl substituents.
• Therefore Br will get attached to the carbon next to benzene ring.
• Hence, the final product would be C₆H₅CHCH₂CH₃
|
Br
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