Chemistry, asked by sushmitakumari141, 9 months ago

According to Nernst equation, which is not correct if
Q = K꜀ :
(a) E꜀ₑₗₗ = 0 (b) RT/nF ln Q = E˚꜀ₑₗₗ
(c) K꜀ = e nFE˚/RT
(d) E꜀ₑₗₗ = E˚꜀ₑₗₗ

Answers

Answered by King99041
1

Answer:

Question itself not readable properly

Answered by techtro
2

According to Nernst equation, option which is not correct if Q = K꜀ is:

• At equilibrium, Q = Keq and also ∆G = 0

• Nernst equation is given as :

E = E° - RT/nF×lnQ

• Here Q = Keq

So, E = E° - RT/nF×lnKeq

• We know that, ∆G = -nFE

But ∆G = 0

•°• E = 0

• We have,

0 = E° - RT/nF×lnKeq

E° = RT/nF×lnKeq

lnKeq = E°nF/RT

Keq = e^E°nF/RT

• Now let us check options.

• Option (d) is not correct because at equilibrium, Ecell = 0

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