Question

according to nielsen media research, the average number of hours of tv viewing per household per week in the united states is 50.4 hours. suppose the standard deviation is 11.8 hours and a random sample of 42 u.s. households is taken. a. what is the probability that the sample average is more than 52 hours? b. what is the probability that the sample average is less than 47.5 hours? c. what is the probability that the sample average is less than 40 hours? if the sample average actually is less than 40 hours, what would it mean in terms of the nielsen media research figures?​

Answer 1

please mark as the brainliest

please

Answer 2

Answer:

a) 0.1898

b)0.0557

c)0.0001

Step-by-step explanation:

a)z=(x-mean)/sigma/sqrt(n)

> (52-50.4)/11.8/sqrt(42)=1.6/1.82=0.1898

probability is 0.1898

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b)< (47.5-50.4)/11.8/sqrt(42)=less than -2.9/1.821 or < z of -1.592

Probability is 0.0557

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c)<-10.4/1.821 or z< -5.711

This is <<0.0001