According to the reaction 3 Fe (s) + 4H2O (l) → Fe3O4(s) +4H2 (g) How many
grams of Fe3O4 would be produced by 36.0 g of water?
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Explanation:
4 moles of H2O produce 1 mole of Fe3O4
so 2 moles of H2O will produce 1/2 mole of Fe3O4
so 115.75g
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