According to vsepr theory give molecular geometry of h2s
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S will contribute 2 electrons
2 H's will contribute 1 electron each to form 2 S-H single bond. therefore bonding electrons=2+2=4
S has 6 electron in outer orbital & 2 H's 1 e each.
thus, Total electrons = 6+2 = 8 e
T.E (8e) - B.E (4e) = 4e = 2 lone pairs. ie 2×2e
will give a V-shaped or bent like structure
the lone pairs will be located in axial position & the rest b. p will be in equatorial
2 H's will contribute 1 electron each to form 2 S-H single bond. therefore bonding electrons=2+2=4
S has 6 electron in outer orbital & 2 H's 1 e each.
thus, Total electrons = 6+2 = 8 e
T.E (8e) - B.E (4e) = 4e = 2 lone pairs. ie 2×2e
will give a V-shaped or bent like structure
the lone pairs will be located in axial position & the rest b. p will be in equatorial
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