Question

Account for the following
The treatment of an alkyl chloride with (aq ) KOH leads to the formation of alcoholic whereas in presence of alcoholic KOH, alkene is the major product​

Answer 1

OH− ion is a strong nucleophile, which can easily substitute the strong leaving chloride ion and leads to the formation of alcohol. On the other hand, alkyl chloride containing β-hydrogen atom with alcoholic KOH solution undergo elimination reaction to give alkene as major product.

Answer 2

OH− ion is a strong nucleophile, which can easily substitute the strong leaving chloride ion and leads to the formation of alcohol. On the other hand, alkyl chloride containing β-hydrogen atom with alcoholic KOH solution undergo elimination reaction to give alkene as major product.