acetamide reacts with Br2/NaOH to give *
O acetyl bromide
O ethyl amine
O alpha-bromo acetamide
O methylamine
Answers
Answered by
1
Answer:
CH
3
CONH
2
+Br
2
+4NaOH
Δ
CH
3
NH
2
+Na
2
CO
3
+2NaBR+2H
2
O
This is Hoffmann's bromamide reaction or Hoffmann's degradation reaction.
Answered by
3
Answer:
methylamine
Explanation:
Br2 is Bromine NaOH reacting with acetamide makes methylamine
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