Acetylene react with alcoholic koh
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There is a vast difference between using the same reagent in two different solvents as in here.
Basically, when we use Alcoholic potassium hydroxide i.e, KOH as a reagent, the negative part of the reagent, that is OH- it acts a a base and abstracts the beta Hydrogen from the saturated substrate( alkyl hallide) present and trasforms it to an alkene in the product, thereby undergoing Elimination reactio
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Alcoholic, KOH , specially in ethylene alcohol, produce C2H5O- ions. These ions are stronger base than OH- ion. Thus they abstracts the ß-hydrogen of alkyl halide to produce alkenes. ... When alkyl chlorides are reacted with aqueous KOH, it leads to substitution whereas alcoholic KOH leads to elimination
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