Question

Acid content of 600ml mixture is 52. if the acid content is to be made into 80, how much pure acid should be added

Answer 1

x% of 600 = 52
(x/100)*600 = 52 or 6*x = 52
x = 52/6 = 8.66%
8.66%of x = 80
x = (80*100)/8.66 = 923.78

Answer 2

Answer : The amount of pure acid should be added, 840 ml

Solution :

First we have to calculate the initial amount of acid.

Initial amount of acid = $600\times \frac{52}{100}=312ml$

Now we have to calculate the amount of pure acid should be added.

Let the amount of pure acid added be 'x' and the equation become,

$(312+x)=\frac{80}{100}\times (600+x)$

By solving the term x, we get

x = 840

Hence, the amount of pure acid should be added, 840 ml