Chemistry, asked by SnehaReddy8869, 11 months ago

Action of caustic soda and chlorin an ethyl alcohol gives

Answers

Answered by theophilussam11

0

Explanation:

When chlorine reacts with ethyl alcohol in the presence of KOH, chloroform is obtained as a final product.

Cl2+CH3CH2OH⟶CH3CHO+2HCl [oxidation]

CCl3CHO+KOH⟶HydrolysisCHCl3+HCOOK.

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