Question

Activity 3
Look at the figure
The heights of the triangle ADC
and triangle BDC are
(1 CC1ult 18 (11h.
61
!
1
MO1
-----5
-5-
B
--5-
Area of the triangle ADC-
1
x 5x6 = 15 sq. cm
2
*S*6
Area of the triangle BDC - 5x6-15 sq. cm
2
Ratio of areas of these triangles
15:15 - 1:1
Ratio in which CD divides AB is 5 : 5 = 1:1
That is, a line CD drawn from the vertex C to its opposite side divides the side and
area of the triangle in the same ratio.
Look at the picture below.
6
1
1
А
IM D
B
- 4
Area of the triangle ADC
Area of the triangle BDC​

Answer 1

Answer:

yyueue9ehgeie0egfeieoege