Math, asked by rasalsujay07, 5 hours ago

Activity (II): Start 13 1 x2 23 x √8 4 V6 1 + 10/6 : 3 xV2 +3 x3 55 √5 x 31 465 :5 End​

Answers

Answered by varnikanarne30
0

Answer:

Given equation is x  

2

−(  

3

+1)x+  

3

=0

(x−  

2

3

+1

)  

2

+  

3

−(  

2

3

+1

)  

2

=0

(x−  

2

3

+1

)  

2

+  

3

−  

4

4+2  

3

 

=0

(x−  

2

3

+1

)  

2

+  

3

−1−  

2

3

 

=0

(x−  

2

3

+1

)  

2

=1−  

2

3

 

 

(x−  

2

3

+1

)  

2

=(  

2

3

−1

)  

2

 

x−  

2

3

+1

=±  

2

3

−1

 

x=  

3

,1

Similar questions