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Can you still recall how to find the factors of a polynomial using the Common Monomial Factor? Supply the
missing answers.
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Solution :-
1) 3a - a²
→ a(3 - a)
So,
→ Common Monomial Factor = a
→ Factored form = (3 - a)
2) 6a²b² - 15a⁵b
→ 3a²b(2b - 5a³)
So,
→ Common Monomial Factor = 3a²b
→ Factored form = (2b - 5a³)
3) 60x² - 70x⁴
→ 10x²(6 - 7x²)
So,
→ Common Monomial Factor = 10x²
→ Factored form = (6 - 7x²)
4) 6x⁴ - 15x³ + 21x²
→ 3x²(2x² - 5x + 7)
So,
→ Common Monomial Factor = 3x²
→ Factored form = (2x² - 5x + 7)
5) 10a²b³c⁴ - 15a⁵b²c⁴ + 30a³b³c²
→ 5a²b²c²(2bc² - 3a³c² + 6ab)
So,
→ Common Monomial Factor = 5a²b²c²
→ Factored form = (2bc² - 3a³c² + 6ab)
Learn more :-
solution of x minus Y is equal to 1 and 2 X + Y is equal to 8 by cross multiplication method
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