Question

actually I want to check whether my answer is correct or not

Answer 1

Ok i will answer it..... see

(1) P(no tail)
$= \frac{189}{729}$
${p} \: of \: one \: tail = \frac{297}{729}$
and probability of two tail
$= \frac{243}{729}$

And its your choice to divide it to simpler form or not

probability of no tail is = 7/27 and probability of one tail =11/27

and probability of two tails =1/3

Answer 2

HII BUDDY

HOPE SO THAT YOU ARE DOING WELL

HERE YOU GO

AS YOU HAVE ALREADY SOLVED AND HAVE A DOUBT SO LET ME GIVE YOU AN EXAMPLE

Two coind are tossed simultaneously 500 times with the following frequencies of different outcomes:
Two heads: 95 times
One tail: 290 times
No head: 115 times
Find the probability of occurrence of each of these events.

Answer :
Given,
Total number of trials = 500 times
Probability (E) = possible outcomes
$\div by \: total \: no \: of \: outcomes$

P (getting two heads) = 0.19
P (getting one tail) =0 .58
P (getting no head) = 0.23