Math, asked by stusujalprajapathi70, 4 months ago

multiply 2 X + 5 by 4 x minus 3​

Answers

Answered by kulkarninishant346
0

Answer:

Step-by-step explanation

Algebraic expressions:

A combination of constants and variables connected by any or all of the four fundamental operations +, -,×,÷ is called an algebraic expression

Multiplication of algebraic expression:

The product of two factors with like signs is positive and the product of two factors with unlike signs is negative.

Multiplication of a binomial  and the binomial:

 

Let  ( a+b)&  (c+d) are two Binomials. By using distributive law of multiplatinum over addition twice, we may find their product

( a+b)× (c+d)

= a(c+d) + b( c+d)

=(a ×  c+a ×  d)+(b ×  c+b × d)

= ac+ad+bc+bd

This method is known as the horizontal method.

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Solution:

i)

(2x + 5)(4x - 3)

2x(4x - 3)+ 5 (4x-3)

= 2x x 4x - 2x x 3 + 5 x 4x - 5 x 3

= 8x² - 6x + 20x -15

= 8x² + 14x -15

ii) ( y - 8)(3y - 4)

y(3y - 4)-8(3y - 4)

= y x 3y - 4y - 8 x 3y + 32

= 3y² - 4y - 24y + 32

= 3y² - 28y + 32

iii) (2.5l - 0.5m)(2.5l + 0.5m)

 

2.5l (2.5l + 0.5m) -0.5m(2.5l + 0.5m)

= 2.5l × 2.5l + 2.5l ×0.5m -0.5m× 2.5l + 0.5m× 0.5m

= 6.25l² +1.25lm – 1.25lm + 0.25n²

= 6.25l² - 0.25m²

iv)( a+3b)(x+5)

a(x+5)+3b(x+5)

ax + 5a + 3b x + 15b

v) (2pq+3q²)(3pq-2q²)

2pq(3pq-2q²) + 3q²(3pq-2q²)

2pq x 3pq - 2pq x 2q² + 3q²x 3pq - 3q2 x 2q²

= 6p²q² - 4pq³ + 9pq³- 6q⁴

= 6p²q² + 5pq³ - 6p⁴

 

vi) ( 3a²/4+3b²)(4(a² -2b²/3))

( 3a²/4+3b²)(4a² -8b²/3)

=3a²/4((4a² -8b²/3)+ 3b²(4a² -8b²/3)

= 3a⁴-2a²b²+12a²b²-8b⁴

= 3a⁴+10a²b²-8b⁴

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Hope this will help you....

Answered by yasinreza2004
0

Answer:

8x^2+14x-15

Step-by-step explanation:

(2x+ 5)(4x-3)

=2x(4x-3) +5(4x-3)

=8x^2 -6x +20x-15

=8x^2+14x-15

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