ad and bd are equal perpendiculars to a line segment ab. Show that cd bisects ab
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Answer:
Let the middle point be O
Given -
AD =BD
Angle A = Angle B (each 90°)
Angle DOA = Angle BOC (vertically opposite angles)
So by AAS we can say that both the triangles are congruent
And AO = BO
Step-by-step explanation:
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Question :-
AD and BC are equal perpendiculars to a line segment AB (see figure). Show that CD bisects AB.
Answer :-
In ∆BOC and ∆AOD, we have
∠BOC = ∠AOD
BC = AD [Given]
∠BOC = ∠AOD [Vertically opposite angles]
∴ ∆OBC ≅ ∆OAD [By AAS congruency]
⇒ OB = OA [By C.P.C.T.]
i.e., O is the mid-point of AB.
Thus, CD bisects AB.
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