AD and CE are the angle bisectors of angle A and angle C respectively.if angle ABC=90,then find angle AOC.
ritvikjain2090ow0ydl:
where is o?
Answers
Answered by
14
Angle AOC= 90+ANGLE B/2
=90+45
=135 degrees
=90+45
=135 degrees
Answered by
94
hello,
let the ΔABC with bisectors of ∠A and ∠C meet BC at D and BA at E
the intersection point be O
∠B=90°
let ∠EAD=∠DAC=x
and ∠ECD=∠ECA=y
in ΔABC,
∠A+∠B+∠C=180°
∠A=x+x=2x
∠C=y+y=2y
⇒90°+2x+2y=180° (angle sum property of triangle)
2(x+y)=90°
x+y=45°
in ΔAOC,
∠OAC+∠OCA+∠AOC=180° (angle sum property of triangle)
x+y+∠AOC=180°
45°+∠AOC=180°
∠AOC=135°
hope this helps,if u like please mark it as brainliest
let the ΔABC with bisectors of ∠A and ∠C meet BC at D and BA at E
the intersection point be O
∠B=90°
let ∠EAD=∠DAC=x
and ∠ECD=∠ECA=y
in ΔABC,
∠A+∠B+∠C=180°
∠A=x+x=2x
∠C=y+y=2y
⇒90°+2x+2y=180° (angle sum property of triangle)
2(x+y)=90°
x+y=45°
in ΔAOC,
∠OAC+∠OCA+∠AOC=180° (angle sum property of triangle)
x+y+∠AOC=180°
45°+∠AOC=180°
∠AOC=135°
hope this helps,if u like please mark it as brainliest
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