AD,BE and CF are altitudes of triangle are equal. Find 2 right angles with RHS criteria.
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use RHS CRITERIA
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Step-by-step explanation:
Given:-
AD,BE and CF are altitudes of triangle are equal.
To find:-
ABC is an equilateral triangle.
Solution:-
In right-angle triangles BCE and CBF, we have,
BC = BC (common hypotenuse);
BE = CF (given).
Hence BCF and CBF are congruent, by RHS theorem. Comparing the triangles, we get ∠B=∠C.
This implies that
AC = AB (sides opposite to equal angles).
Similarly,
AD = BE ⇒∠B =∠A
⇒ AC = BC
✿Together, we get AB = BC = AC or △ABC is equilateral. [hence proved]
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