Question

AD is a diameter of a circle and AB is a chord if AD=30cm and AB=24cm then the distance of AB from the centre of the circle is​

Answer 1

Step-by-step explanation:

hence then the distance of AB from the centre of the circle is 9cm

Answer 2

Answer:

let join the center to the one end of chord and perpendicular line from center to chord. this form a right angle triangle.

X^2= 15^2 - 12^2

X = 9