Question

AD is a diameter of a circle and AB is a chord. If AD = 34cm, AB = 30cm, the distance of AB from the centre of the circle isAnswer

Answer 1

the distance of AB from the centre of the circle is 4cm

Answer 2

let o be the center of the circle and the perpendicular height be OX.
AD=34 cm=2.OA
OA=17 cm
AB=30 cm
AX=15cm      (by theorem)

In triangle AOX,
OX sq=OA sq -AX sq
          =289 - 225=64
OX= 8 cm