AD is a median of a triangle ABC. Prove that AB + AC > 2AD
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ab = x +ac =x
x+x =xsquare
2Ad =x+x=x square
then ab+ ac =xsquare and then 2AD =x square
this is proof that AB+AC is not greater than 2AD
x+x =xsquare
2Ad =x+x=x square
then ab+ ac =xsquare and then 2AD =x square
this is proof that AB+AC is not greater than 2AD
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1
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