AD is a median of triangle ABC. Prove that AB + AC > 2 AD.
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IN THAT TRIANGLE ......
FROM THE PROPERTY OF SIDES OF A TRIANGLE W3 HAVE.
AB+BD>AD (EQUATION 1 ) &
DC+AC>AD (EQUATION 2) .
BY ADDING BOTH EQUATIONS WE HAVE...
AB+BD+DC+AC>AD+AD
AB+BD+DC+AC>2AD
AB+BC+AC>2AD
FROM THE PROPERTY OF SIDES OF A TRIANGLE W3 HAVE.
AB+BD>AD (EQUATION 1 ) &
DC+AC>AD (EQUATION 2) .
BY ADDING BOTH EQUATIONS WE HAVE...
AB+BD+DC+AC>AD+AD
AB+BD+DC+AC>2AD
AB+BC+AC>2AD
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