factorise the following a^4-1/b^4
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a^4-(1/b)^4
=(a^2)^2-(1/b^2)^2
a^2-b^2=(a+b)(a-b)
=(a^2+1/b^2)(a^2-1/b^2
=(a^2)^2-(1/b^2)^2
a^2-b^2=(a+b)(a-b)
=(a^2+1/b^2)(a^2-1/b^2
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