AD is an altitude of an equilateral triangle ABC. On AD as base another equilateral triangle ADE is constructed. Prove that ar(ADE): ar(ABC)=3:4
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In triangle ABC let Side be of r length
that is AD equal to 1.73rby 4
Prove that the Triangle ABC is Similar to Triangle ADE
Area of triangles ABC by Area of triangles ADE equal to
AB× AB by AD×AD = r× r ÷ 3r×r÷4
= 4÷3
that is AD equal to 1.73rby 4
Prove that the Triangle ABC is Similar to Triangle ADE
Area of triangles ABC by Area of triangles ADE equal to
AB× AB by AD×AD = r× r ÷ 3r×r÷4
= 4÷3
JessicaMalik:
Ty^_^
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