Question

Ad is an altitude of an equilateral triangle ABC. Show that AD bisects angle A​

Answer 1

Answer:

AB=AC(given)

∴∠ABC=∠ACB=θ

ADaltitude

Then,

∠ADB=∠ADC=90

0

Hence∠BAD=∠DAC

ADbisect∠A

Answer 2

Answer

Given- Triangle ABC is a equilateral triangle and AD is the altitude

To proof- AD bisects angle A

in triangle ACD and triangle ABD

AC=AB (Given as ABC is an equilateral triangle)

<C=<B (given)

AD=AD (comman)

so by SAS these triangle are congurent

By CPCT <dac = <bad thearefore  AD biscets angle A