Question

AD is an altitude of an isosceles triangle ABC,if AB=AC and <B=40°then the value of <CAD is ​

Answer 1

Answer:

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Answer 2

Answer:

50 degrees

Step-by-step explanation:

AD is an altitude; means it divides angle A into 2 equal parts ; ANGLE BAD AND ANGLE CAD

Therefore Angle CAD = Angle BAD

AB = AC

USING THEOREM

IF TWO SIDES OF AN ISOSCELES TRIANGLE ARE EQUAL THEN THE ANGLES OPPOSITE TO EQUAL SIDES ARE EQUAL.

Therefore Angle ABD = Angle ACD

AND ANGLE ABD IS GIVEN AS 40 DEGREES

SO ANGLE ACD IS ALSO 40 DEGREES.

USING ANGLE SUM PROPERTY.

SUM OF 3 ANGLES OF A TRIANGLE IS 180 DEGREES.

THEREFORE, Angle A = 180 -[40 + 40]

ANGLE A = 100 DEGREES

AND AD DIVIDES ANGLE A

SO ANGLE CAD = ANGLE BAD = 50 DEGREES

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