ad is an altitude of an isosceles triangle ABC in which ab is equal to AC show that ad bisect bc
Answers
Answered by
5
I hope you got it...
Attachments:
Answered by
8
in ∆ABD and ∆ADC,
AB=BC. (given)
AD=AD. (COMMON)
angleADB = angleADC. (90° )
therefore, ∆ABD is congruent to ∆ADC.
BD = DC. ( cpct)
AB=BC. (given)
AD=AD. (COMMON)
angleADB = angleADC. (90° )
therefore, ∆ABD is congruent to ∆ADC.
BD = DC. ( cpct)
Similar questions