Question

AD is an altitude of an isosceles triangle ABC in which AB = AC Show that A D bisects BC and AD bisects angleA.

Answer 1

In BDA AND CDA
AB= AC -GIVEN
AD=AD- COMMON
B = C- OPPOSITE ANGLES ARE EQUAL
BY SAS CONGRUENCE
BDA CONGRUENCE TO CDA
BY CPCT
BD= DC
THEREFORE. AD BISECT BC

Answer 2

CRM

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