Question

AD is an altitude of an isosceles triangle ABC where AB=AC.show that AB bisect BC.

Answer 1

Given:-

ABC is a isosceles triangle.

AD is perpendicular on BC.

AB=BC

To prove:-

In Triangle ACD AND ABD,

AD=AD (Common)

AC=AB (Given)

Angle ADC=Angle ADB (90 degree

each)

Hence,Triangle ACD=ABD (By SAS)

Therefore,AD bisects BC. (By

C.P.C.T.)

HENCE,PROVED.

PLS MRK BRAINLIEST!!

Answer 2

CRM

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