Math, asked by subuhifathima002, 10 months ago

AD is an altitude of an isosceles tringleABC in which AB=AC.show that AD bisects BC

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Answered by Anonymous

14

Answer:

AD is an altitude of an isosceles triangle ABC in which AB = AC. (ii) AD bisects ∠A. ∴ BD = CD | C.P.C.T. ⇒ AD bisects BC.

Answered by sharmabadahein76

1

Answer:

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