AD is median of triangle ABC is it true that AB+AC+BC>2AD
Answers
Answered by
10
Here's your answer!!
____________________________
It's given that,
AD is the median of the ∆ABC,
It means, BD=CD
Because the median divides the line into two equal parts.
So,
<BAD =<CAD ( as AD is median and bisecting <BAC at A)
We know that,
In triangle Sum of two sides is Always greater than the third one.
So,
=> AB + BD > AD......(i)
And,
=>AC +CA > AD ......(ii)
Adding equation (i) and (ii), we get :-
=>AB +BD +AC+CA >2AD
=>AB + BC + CA > 2AD ( Since, BD +AC =AC )
Hence, Proved
_______________________________
Hope it helps you!! :)
____________________________
It's given that,
AD is the median of the ∆ABC,
It means, BD=CD
Because the median divides the line into two equal parts.
So,
<BAD =<CAD ( as AD is median and bisecting <BAC at A)
We know that,
In triangle Sum of two sides is Always greater than the third one.
So,
=> AB + BD > AD......(i)
And,
=>AC +CA > AD ......(ii)
Adding equation (i) and (ii), we get :-
=>AB +BD +AC+CA >2AD
=>AB + BC + CA > 2AD ( Since, BD +AC =AC )
Hence, Proved
_______________________________
Hope it helps you!! :)
Attachments:
Similar questions