Question

ad is perpendicular to the side BC of an equilateral triangle ABC prove that 4AD^2=3AB^2

Answer 1

answer is proved in the picture given above .

Answer 2

Step-by-step explanation:

in ∆ADB

=> by Pythagoras theorem

=> a square by 2 + h square = a square

=>a square - a square by 4 = h square

4a square - a square By 4 = h square

=> 3a square = 4h square

=> 3AB square = 4 AD square

HENCE PROVED