Question

adc is a triangle abc and abc are straight lines. EB is parallel to DC. Angle EBC = 148 Angle ADC = 63. Work out the size of angle EAB.

Answer 1

Step-by-step explanation:

<EBA=180-148

=32⁰

<EDC=<AEB=63⁰(corresponding angles of parallel lines EB&CD)

in ∆AEB,

<EAB+<ABE+<AEB=180⁰

<EAB=180-(32+63)

=180-95

=85⁰

Answer 2

Answer:

∠EAB=85°

Step-by-step explanation:

Given : ∠EBC=148°.

so,∠EBA=180°-∠EBC (since ABC is a straight line)

     ∠EBA=180°-148°=32°

Also given EB ║to DC, and ∠ADC=63°

                                      then ∠AEB=63°(pair of corresponding angles)°,

In ΔAEB, ∠AEB+∠EBA+∠EAB=180°

               63° + 32° + ∠EAB =180°

                                  ∠EAB = 180°-95°

                   HENCE  ∠EAB = 85°

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