Math, asked by darshandarshan11083, 19 days ago

Add : 5y (3y² + 2y + 1) and 6(y² - 8y + 2)​

Answers

Answered by dayanidhisharma19
1

Answer:

15y^3 + 22y^2 - 43y + 12

Step-by-step explanation:

5y(3y^2 + 2y + 1) + 6(y^2 - 8y + 2)\\= 15y^3 + 10y^2 + 5y + 12y^2 - 48y + 12\\= 15y^3 + (10+12)y^2 + (5-48)y + 12\\= 15y^3 + 22y^2 - 43y + 12

Answered by pjignesh0412
0

Answer:

15y^3 + 10y^2 + 5y + 6y^2 - 48y + 12

15y^3 + 16y^2 - 43y + 12

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