Question

Add:6ab+7a^2b^2-2ab-a^2b^2 and 6ab+5a^2b^2

Answer 1

Answer:

12ab+12a^2b^2-2ab-a^2b^2

Step-by-step explanation:

Answer 2

\left[a _{1}\right] = \left[ \frac{\left( \frac{-1}{3}\,i \right) \,\sqrt{6}\,\sqrt{ab}}{b}\right][a​1​​]=[​b​​(​3​​−1​​i)√​6​​​√​ab​​​​​]. = 6ab+7a^2b^2-2ab-a^2b^2


\left[a _{2}\right] = \left[ \frac{\left( \frac{1}{5}\,i \right) \,\sqrt{30}\,\sqrt{ab}}{b}\right][a​2​​]=[​b​​(​5​​1​​i)√​30​​​√​ab​​​​​]. =.
6ab+5a^2b^2