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(7√7+4√3) & (4√7-3√3)
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Answer:
If x = √ (7+4√3) /√ (7-4√3) , then what does x² (x-14) ² =? this your correct question
Step-by-step explanation:
Let’s apply this to the question :
x=7+43√√7−43√√
The conjugate of the denominator 7−43–√−−−−−−−√ is 7+43–√−−−−−−−√
Multiply the entire expression by the conjugate to get:
7+43√√7−43√√⋅7+43√√7+43√√
=(7+43√)2√(72−(43√)2)√
=7+43√49−16(3)√
x=7+43√1√
x=7+43–√
also notice that x−14=7+43–√−14=43–√−7
x2(x−14)2=(x(x−14))2
=((43–√+7)(43–√−7))2
Use the difference of squares identity again with a=43–√ and b=7 to get
((43–√+7)(43–√−7))2=(48−49)2
=(−1)2=1
∴x2(x−14)2=1
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