Math, asked by Sushmahoney, 9 hours ago

Find the equation of the tangent at that point 30 degrees of the circle x^2+y^2+4x+6y-39=0

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Answered by AtikRehan786

2

Equation of the tangent is ^

Equation of the circle is x2 + y2 + 4x + 6y – 39 = 0 g = 2, f = 3, r = √(4 + 9 + 39) = √52 = 2√3 θ = 30° Equation of the tangent is

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